(2x-4)^2-35/5=29

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Solution for (2x-4)^2-35/5=29 equation: 



(2x-4)^2-35/5=29

We move all terms to the left:

(2x-4)^2-35/5-(29)=0

determiningTheFunctionDomain
(2x-4)^2-29-35/5=0

We add all the numbers together, and all the variables

(2x-4)^2-36=0

We move all terms containing x to the left, all other terms to the right

(2x-4)^2=36

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